{"id":282,"date":"2020-10-29T17:45:38","date_gmt":"2020-10-29T17:45:38","guid":{"rendered":"https:\/\/dochoihoangha.com\/edu\/?p=282"},"modified":"2020-10-29T17:45:38","modified_gmt":"2020-10-29T17:45:38","slug":"de-tai-ca-tom-cua-dong-vat-duoi-nuoc-nhom-tuoi-24-36-thang","status":"publish","type":"post","link":"https:\/\/dochoihoangha.com\/edu\/de-tai-ca-tom-cua-dong-vat-duoi-nuoc-nhom-tuoi-24-36-thang.html","title":{"rendered":"\u0110\u1ec1 t\u00e0i: C\u00e1 \u2013 T\u00f4m \u2013 Cua (\u0111\u1ed9ng v\u1eadt d\u01b0\u1edbi n\u01b0\u1edbc) – Nh\u00f3m tu\u1ed5i: 24 \u2013 36 th\u00e1ng"},"content":{"rendered":"

Gi\u00e1o \u00e1n nh\u1eadn bi\u1ebft t\u1eadp n\u00f3i<\/a> – Ch\u1ee7 \u0111i\u1ec3m: \u0111\u1ed9ng v\u1eadt s\u1ed1ng d\u01b0\u1edbi n\u01b0\u1edbc
\n\u0110\u1ec1 t\u00e0i : C\u00e1 \u2013 T\u00f4m \u2013 Cua
\nNh\u00f3m tu\u1ed5i : 24 \u2013 36 th\u00e1ng<\/p>\n

I. M\u1ee5c \u0111\u00edch y\u00eau c\u1ea7u :<\/h2>\n

1 . Gi\u00e1o d\u01b0\u1ee1ng :<\/strong><\/p>\n

+ Ki\u1ebfn th\u1ee9c :<\/p>\n

Tr\u1ebb nh\u1eadn bi\u1ebft v\u00e0 g\u1ecdi t\u00ean con c\u00e1, con t\u00f4m, con cua.<\/p>\n

Nh\u1eadn ra m\u1ed9t s\u1ed1 b\u1ed9 ph\u1eadn ch\u00ednh tr\u00ean c\u01a1 th\u1ec3 con v\u1eadt.<\/p>\n

Bi\u1ebft m\u1ed9t s\u1ed1 \u0111\u1eb7c \u0111i\u1ec3m n\u1ed5i b\u1eadt c\u1ee7a con v\u1eadt \u0111\u00f3 ( v\u1ea3y, ch\u00e2n, c\u00e0ng<\/em> )<\/p>\n

Bi\u1ebft \u0111\u01b0\u1ee3c nh\u1eefng con v\u1eadt n\u00e0y \u0111\u1ec1u s\u1ed1ng d\u01b0\u1edbi n\u01b0\u1edbc. Th\u1ecbt c\u00e1c con n\u00e0y r\u1ea5t ngon v\u00e0 b\u1ed5.<\/p>\n

+ Ph\u00e1t tri\u1ec3n ng\u00f4n ng\u1eef :<\/strong><\/p>\n

T\u1eadp tr\u1ebb r\u00fat ra nh\u1eadn x\u00e9t b\u1eb1ng t\u1eeb ng\u1eef c\u1ee7a tr\u1ebb khi quan s\u00e1t c\u00e1c con v\u1eadt.<\/p>\n

T\u1eadp di\u1ec5n \u0111\u1ea1t v\u00e0 m\u00f4 t\u1ea3 theo m\u1eabu : \u0111\u00e2y l\u00e0 con g\u00ec ? Con c\u00e1 \u0103n g\u00ec ?\u2026<\/p>\n

Ph\u00e1t tri\u1ec3n c\u1ea3m x\u00fac :<\/p>\n

2. K\u1ef9 n\u0103ng :<\/strong><\/p>\n

Luy\u1ec7n t\u1eadp k\u1ef9 n\u0103ng quan s\u00e1t, tr\u1ea3 l\u1eddi \u0111\u00fang y\u00eau c\u1ea7u c\u1ee7a c\u00f4.<\/p>\n

T\u1eadp cho tr\u1ebb s\u1ee7 d\u1ee5ng t\u1eeb ng\u1eef \u0111\u1ec3 di\u1ec5n \u0111\u1ea1t cho ng\u01b0\u1eddi kh\u00e1c hi\u1ec3u trong khi quan s\u00e1t v\u1eadt.<\/p>\n

C\u1ee7ng c\u1ed1 k\u1ef9 n\u0103ng x\u1ebfp theo h\u00ecnh d\u1ea1ng, kho\u1ea3ng c\u00e1ch.<\/p>\n

3. Gi\u00e1o d\u1ee5c :<\/strong><\/p>\n

C\u00e1, t\u00f4m, cua \u0103n ngon v\u00e0 b\u1ed5. Khi \u0103n c\u01a1m c\u00f3 c\u00e1, t\u00f4m, cua nh\u1edb \u0103n nhi\u1ec1u.<\/p>\n

4. B\u1ed9 m\u00f4n k\u1ebft h\u1ee3p :<\/strong><\/p>\n

\u00c2m nh\u1ea1c<\/p>\n

T\u1ea1o h\u00ecnh<\/p>\n

Gi\u00e1o d\u1ee5c th\u1ec3 ch\u1ea5t<\/p>\n

II. Chu\u1ea9n b\u1ecb :<\/h2>\n

+ V\u1eadt th\u1eadt : 3 c\u00e1i h\u1ed9p c\u00f3 c\u00e1, t\u00f4m, cua.<\/p>\n

+ Tranh t\u00f4m, cua, c\u00e1.<\/p>\n

+ 1 s\u1ed1 c\u00e1, t\u00f4m, cua nh\u1ef1a m\u1ed7i tr\u1ebb m\u1ed9t r\u1ed5.<\/p>\n

III H\u01b0\u1edbng d\u1eabn ho\u1ea1t \u0111\u1ed9ng : <\/u><\/h2>\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n
\n

Ho\u1ea1t \u0111\u1ed9ng c\u1ee7a c\u00f4<\/h2>\n<\/td>\n

Ho\u1ea1t \u0111\u1ed9ng c\u1ee7a tr\u1ebb<\/strong><\/td>\n<\/tr>\n
\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 * Ho\u1ea1t \u0111\u1ed9ng 1<\/u> <\/strong>:<\/td>\n <\/td>\n<\/tr>\n
C\u00f4 ch\u00e1u c\u00f9ng h\u00e1t b\u00e0i \u201c \u0110i c\u00e2u c\u00e1\u201d<\/td>\nTr\u1ebb h\u00e1t theo c\u00f4<\/td>\n<\/tr>\n
C\u00f4 cho tr\u1ebb quan s\u00e1t con cua v\u00e0 h\u1ecfi tr\u1ebb :<\/p>\n

–\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u0110\u00e2y l\u00e0 con g\u00ec ?<\/p>\n

–\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 Con cua c\u00f3 g\u00ec ?<\/p>\n

–\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 B\u1ea1n n\u00e0o bi\u1ebft con cua b\u00f2 l\u00e0m sao ?<\/td>\n

Tr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
C\u00f4 \u0111\u1ecdc b\u00e0i \u0111\u1ed3ng dao :<\/p>\n

\u201c B\u00e0 c\u00f2ng \u0111i ch\u1ee3 \u0111\u01b0\u1eddng xa. C\u00e1i t\u00f4m, c\u00e1i t\u00e9p \u0111i sau l\u01b0ng b\u00e0 c\u00f2ng\u201d<\/td>\n

 <\/td>\n<\/tr>\n
– B\u1ea1n n\u00e0o cho bi\u1ebft con n\u00e0o \u0111i sau l\u01b0ng b\u00e0 c\u00f2ng ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
– C\u00f4 ch\u00e1u ta c\u00f9ng xem con t\u00f4m c\u00f3 g\u00ec nh\u00e9 ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
Sau \u0111\u00f3 c\u00f4 t\u00f3m l\u1ea1i : Con t\u00f4m c\u00f3 nhi\u1ec1u ch\u00e2n, b\u01a1i d\u01b0\u1edbi n\u01b0\u1edbc, nh\u1ea3y tanh t\u00e1ch.<\/td>\n <\/td>\n<\/tr>\n
C\u00f4 cho tr\u1ebb \u0111\u1ecdc th\u01a1 b\u00e0i \u201c Con c\u00e1 v\u00e0ng \u201c<\/td>\n <\/td>\n<\/tr>\n
C\u00f4 h\u1ecfi : \u0111\u00e2y l\u00e0 con g\u00ec ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
– C\u00e1c con nh\u00ecn xem con c\u00e1 c\u00f3 g\u00ec ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
C\u00f4 t\u00f3m l\u1ea1i : con c\u00e1 b\u01a1i d\u01b0\u1edbi n\u01b0\u1edbc, c\u00f3 v\u1ea3y, c\u00f3 \u0111u\u00f4i.<\/td>\n <\/td>\n<\/tr>\n
\u00a0<\/u><\/strong><\/p>\n

\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 * Ho\u1ea1t \u0111\u1ed9ng 2 : <\/u><\/strong><\/td>\n

\u00a0<\/u><\/strong><\/td>\n<\/tr>\n
C\u00f4 c\u00f3 m\u1ed9t s\u1ed1 tranh r\u1ea5t l\u00e0 \u0111\u1eb9p, c\u00f4 \u0111\u1ed1 c\u00e1c b\u1ea1n xem tranh g\u00ec nh\u00e9.<\/p>\n

C\u00f4 \u0111\u1ecdc c\u00e2u \u0111\u1ed1 : \u201c Con g\u00ec nh\u1ea3y tanh t\u00e1ch, c\u00f3 nhi\u1ec1u ch\u00e2n\u201d<\/td>\n

Tr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
Con h\u00e3y ch\u1ecdn tranh c\u00f3 con v\u1eadt \u0111\u00f3 cho c\u00f4 xem n\u00e0o ?<\/td>\nTr\u1ebb ch\u1ecdn<\/td>\n<\/tr>\n
Con t\u00f4m s\u1ed1ng \u1edf \u0111\u00e2u ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
C\u00f4 \u0111\u1ed1 ti\u1ebfp : \u201c C\u00f3 c\u1ea3y c\u00f3 \u0111u\u00f4i kh\u00f4ng \u0111i tr\u00ean c\u1ea1n l\u1ea1I \u0111i d\u01b0\u1edbi h\u1ed3.\u201d<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
–\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 \u00c0 ! C\u00e1c con gi\u1ecfi l\u1eafm<\/p>\n

( C\u00f4 k\u00eau tr\u1ebb l\u00ean ch\u1ecdn tranh)<\/td>\n

 <\/td>\n<\/tr>\n
M\u00ecnh c\u00e1 c\u00f3 g\u00ec v\u1eady ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
C\u00e1 th\u00edch \u0103n g\u00ec ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
C\u00f4 \u0111\u1ed1 : \u201c Con g\u00ec t\u00e1m c\u1eb3ng, hai c\u00e0ng, b\u00f2 ngang\u201d<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
C\u00f4 k\u00eau tr\u1ebb l\u00ean ch\u1ecdn tranh.<\/td>\nTr\u1ebb ch\u1ecdn<\/td>\n<\/tr>\n
– Cua s\u1ed1ng \u1edf \u0111\u00e2u ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
C\u00f4 t\u00f3m l\u1ea1i : nh\u01b0 v\u1eady l\u00e0 c\u1ea3 t\u00f4m, cua \u0111\u1ec1u s\u1ed1ng d\u01b0\u1edbI n\u01b0\u1edbc.<\/td>\n <\/td>\n<\/tr>\n
\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 * Ho\u1ea1t \u0111\u1ed9ng 3 : tr\u00f2 ch\u01a1i v\u1eadn \u0111\u1ed9ng<\/u><\/strong><\/td>\n\u00a0<\/u><\/strong><\/td>\n<\/tr>\n
C\u00f4 cho ch\u00e1u ch\u01a1i tr\u00f2 ch\u01a1i \u201c \u0110i ch\u1ee3 \u201d<\/td>\n <\/td>\n<\/tr>\n
B\u00e9 \u0111\u1ebfn r\u1ed5 l\u1ea5y t\u00f4m, cua, c\u00e1 ( nh\u1ef1a )<\/td>\n <\/td>\n<\/tr>\n
– B\u00e2y gi\u1edd c\u00e1c con\u00a0 h\u00e3y s\u1eafp x\u1ebfp con c\u00f3 v\u1ea3y, \u0111u\u00f4i \u0111\u1eb7t ra ngo\u00e0i .<\/td>\nTr\u1ebb x\u1ebfp<\/td>\n<\/tr>\n
– C\u00e1c con h\u00e3y x\u1ebfp con g\u00ec nh\u1ea3y tanh t\u00e1ch ri\u00eang.<\/td>\nTr\u1ebb x\u1ebfp<\/td>\n<\/tr>\n
– R\u1ed3i c\u00e1c con x\u1ebfp con g\u00ec b\u00f2 ngang b\u00ean c\u1ea1nh.<\/td>\nTr\u1ebb x\u1ebfp<\/td>\n<\/tr>\n
– V\u1eady l\u00e0 ch\u00fang ta c\u00f3 \u0111\u1ee7 3 lo\u1ea1i con g\u00ec v\u1eady con ?<\/td>\nTr\u1ebb tr\u1ea3 l\u1eddi<\/td>\n<\/tr>\n
\u00a0\u00a0\u00a0\u00a0\u00a0\u00a0 * Ho\u1ea1t \u0111\u1ed9ng 4 : tr\u00f2 ch\u01a1i v\u1eadn \u0111\u1ed9ng<\/u><\/strong><\/td>\n <\/td>\n<\/tr>\n
– C\u00e1c con \u01a1i ! C\u00e1c con c\u00f3 r\u1ea5t nhi\u1ec1u c\u00e1, t\u00f4m, cua m\u00e0 ch\u01b0a c\u00f3 ao h\u1ed3 \u0111\u1ec3 nu\u00f4i. C\u00e1c con h\u00e3y chia l\u00e0m hai \u0111\u1ed9I \u0111\u1ec3 thi xem ai x\u1ebfp ao cho c\u00e1 nhanh h\u01a1n nh\u00e9.<\/td>\nTr\u1ebb x\u1ebfp<\/td>\n<\/tr>\n
\u1ed2 ! b\u00e2y gi\u1edd c\u00f3 ao r\u1ed3i, hai \u0111\u1ed9i h\u00e3y x\u1ebfp t\u00f4m, cua, c\u00e1 v\u00e0o ao. Nh\u1edb x\u1ebfp l\u00e0m sao cho th\u1eadt nhi\u1ec1u t\u00f4m, cua, c\u00e1 nh\u00e9.<\/td>\nTr\u1ebb x\u1ebfp<\/td>\n<\/tr>\n
C\u00f4 t\u1ed5ng k\u1ebft, tuy\u00ean d\u01b0\u01a1ng \u0111\u1ed9i th\u1eafng v\u00e0 c\u1ea3 l\u1edbp<\/td>\n <\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n

 <\/p>\n

C\u00e1c b\u00e9 nh\u00e0 tr\u1ebb quan s\u00e1t v\u00e0 t\u1eadp n\u00f3i con c\u00e1 v\u00e0ng<\/h2>\n